Percentage change, interest and depreciation

GCSE Maths revision notes, key terms and practice questions.

Percentage change

  • Percentage change = change ÷ original amount × 100. Always divide by the original amount, not the new one.
  • A shop buys a jacket for £40 and sells it for £50. The profit is £10, so the percentage profit is 10 ÷ 40 × 100 = 25%.
  • A price falls from £80 to £68. The decrease is £12, and 12 ÷ 80 × 100 = 15%.

Simple interest

  • Simple interest is the same amount every year, worked out on the original amount only.
  • £400 at 5% simple interest for 3 years earns 400 × 0.05 × 3 = £60.

Compound interest

  • Compound interest is added to the total each year, so the next year's interest is worked out on a bigger amount.
  • Amount = original × multiplierⁿ, where n is the number of years. £400 at 5% compound interest for 3 years: 400 × 1.05³ = £463.05.
  • Over the same time, compound interest earns more than simple interest: £63.05 compared with £60.

Depreciation and repeated changes

  • Depreciation is a loss in value. A £15 000 car that depreciates by 20% a year is worth 15 000 × 0.8² = £9600 after 2 years.
  • Repeated percentage changes multiply: a 10% increase then a 10% decrease is 1.1 × 0.9 = 0.99, which is a 1% decrease overall.

Key terms

Percentage change
Change ÷ original amount × 100.
Profit
The amount gained when something is sold for more than it cost.
Loss
The amount lost when something is sold for less than it cost.
Simple interest
Interest that is the same amount each year, based on the original amount.
Compound interest
Interest added to the total each year, so interest is also earned on interest.
Depreciation
A decrease in value over time.
Per annum
Per year.

Practise Percentage change, interest and depreciation: 12 questions