3D problems with Pythagoras and trigonometry

Level 2 Further Maths revision notes, key terms and practice questions.

Pythagoras in 3D

  • The diagonal of a cuboid with sides a, b and c is √(a² + b² + c²). A 3 × 4 × 12 cuboid has diagonal √(9 + 16 + 144) = √169 = 13.
  • The space diagonal of a cube with side s is s√3.
  • Find lengths step by step: first the diagonal of the base, then use it with the height.

Angles in 3D

  • The angle between a line and a plane is the angle between the line and its projection (shadow) on the plane.
  • Cuboid with base 3 × 4 and height 12: the base diagonal is 5, so the angle between the space diagonal and the base satisfies tan θ = 12 ÷ 5, giving θ = 67.4°.
  • Pyramids: for a square-based pyramid with base side 6 and height 4 (apex above the centre), the half-diagonal is 3√2, so each sloping edge is √(18 + 16) = √34.
  • The angle between two planes is found using lines in each plane that are perpendicular to where the planes meet.

Non-right-angled triangles

  • Sine rule: a/sin A = b/sin B = c/sin C. Use it with a pair of opposite sides and angles.
  • Cosine rule: a² = b² + c² − 2bc cos A. Use it with two sides and the angle between them, or three sides.
  • Area = ½ab sin C. For sides 6 and 8 with an included angle of 30°: ½ × 6 × 8 × sin 30° = 12.

Key terms

Space diagonal
A diagonal passing through the inside of a 3D shape.
Projection
The shadow of a line on a plane.
Plane
A flat surface.
Sine rule
a/sin A = b/sin B = c/sin C.
Cosine rule
a² = b² + c² − 2bc cos A.
Included angle
The angle between two given sides.

Practise 3D problems with Pythagoras and trigonometry: 10 questions