Tangents and normals

Level 2 Further Maths revision notes, key terms and practice questions.

Tangents

  • The tangent to a curve at a point has the same gradient as the curve there.
  • Method: find the y-coordinate, find dy/dx at the point, then use y − y₁ = m(x − x₁).
  • Example: y = x² − 3x + 4 at x = 2. y = 4 − 6 + 4 = 2. dy/dx = 2x − 3 = 1. The tangent is y − 2 = 1(x − 2), so y = x.
  • A tangent with gradient 0 is horizontal.

Normals

  • The normal is perpendicular to the tangent at the same point, so its gradient is −1 ÷ (tangent gradient).
  • For y = x² − 3x + 4 at (2, 2), the normal has gradient −1, so y − 2 = −(x − 2), giving y = −x + 4.
  • For y = x³ at (1, 1): the tangent gradient is 3, so the tangent is y = 3x − 2. The normal has gradient −1/3: y − 1 = −(1/3)(x − 1), giving x + 3y = 4.

Common mistakes

  • Use the gradient at the point, not the gradient function itself.
  • Substitute into the original equation to find y, not into dy/dx.
  • Where lines cross an axis, set x = 0 or y = 0.

Key terms

Tangent to a curve
A straight line touching the curve with the same gradient at that point.
Normal
A line perpendicular to the tangent at the same point.
Point of contact
The point where a tangent touches a curve.
Perpendicular gradient
The negative reciprocal of a gradient.

Practise Tangents and normals: 10 questions